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PowerShell GUI Menus: Best Way to Streamline Your Workflow

Unlock the potential of PowerShell with GUI menus. In this article, we delve into creating intuitive and interactive PowerShell GUI menus using this tool’s capabilities. Discover how to enhance your scripts, automate tasks, and provide a user-friendly experience with dynamic menus that elevate your PowerShell skills to the next level.

Requirements for the PowerShell GUI Menus Making Process

To create a PowerShell GUI (Graphical User Interface), you will need the following requirements:

  1. PowerShell versions 5.0 and later
  2. Windows Operating System
  3. PowerShell Integrated Scripting Environment (ISE) or Code Editor
  4. Windows Presentation Foundation (WPF)

Displaying the Console Window

To build a PowerShell form menu for your PowerShell scripts and control the visibility of the console window, you can follow these steps:

  • Import the required .NET assemblies:
Add-Type -AssemblyName System.Windows.Forms
Import the required .NET assemblies:
  • Create a function to show or hide the console window:
function Show-ConsoleWindow {
    param(
        [bool]$show
    )
    $console = Get-Process -Id $PID | Select-Object -ExpandProperty MainWindowHandle
    $consoleWindow = [System.Windows.Forms.NativeWindow]::new()
    $consoleWindow.AssignHandle($console)
    $consoleWindow.Visible = $show
}
Create a function to show or hide the console window - PowerShell GUI Menus: Best Way to Streamline Your Workflow
  • Create a function to display the form menu:
function Show-FormMenu {
    $form = New-Object System.Windows.Forms.Form
    $form.Text = "PowerShell Form Menu
    $form.Size = New-Object System.Drawing.Size(300, 200)
    $form.FormBorderStyle = [System.Windows.Forms.FormBorderStyle]::FixedSingle

    $buttonShowConsole = New-Object System.Windows.Forms.Button
    $buttonShowConsole.Text = "Show Console"
    $buttonShowConsole.Location = New-Object System.Drawing.Point(50, 50)
    $buttonShowConsole.Size = New-Object System.Drawing.Size(200, 30)
    $buttonShowConsole.Add_Click({ Show-ConsoleWindow -show $true })
    $form.Controls.Add($buttonShowConsole)

    $buttonHideConsole = New-Object System.Windows.Forms.Button
    $buttonHideConsole.Text = "Hide Console"
    $buttonHideConsole.Location = New-Object System.Drawing.Point(50, 100)
    $buttonHideConsole.Size = New-Object System.Drawing.Size(200, 30)
    $buttonHideConsole.Add_Click({ Show-ConsoleWindow -show $false })
    $form.Controls.Add($buttonHideConsole)

    [void]$form.ShowDialog()
}
Create a function to display the form menu
  • Call the Show-FormMenu function to display the form menu: Show-FormMenu

The above code will create a simple form menu with two buttons: “Show Console” and “Hide Console”. Clicking the “Show Console” button will make the console window visible, and clicking the “Hide Console” button will hide the console window.

Menu Options in PowerShell

Here’s an example of how you can create menu options in a PowerShell script using a form:

Add-Type -AssemblyName System.Windows.Forms

function Show-FormMenu {
    $form = New-Object System.Windows.Forms.Form
    $form.Text = "PowerShell Menu"
    $form.Size = New-Object System.Drawing.Size(300, 200)
    $form.FormBorderStyle = [System.Windows.Forms.FormBorderStyle]::FixedSingle

    $buttonOption1 = New-Object System.Windows.Forms.Button
    $buttonOption1.Text = "Option 1"
    $buttonOption1.Location = New-Object System.Drawing.Point(50, 50)
    $buttonOption1.Size = New-Object System.Drawing.Size(200, 30)
    $buttonOption1.Add_Click({ Option1 })
    $form.Controls.Add($buttonOption1)

    $buttonOption2 = New-Object System.Windows.Forms.Button
    $buttonOption2.Text = "Option 2"
    $buttonOption2.Location = New-Object System.Drawing.Point(50, 100)
    $buttonOption2.Size = New-Object System.Drawing.Size(200, 30)
    $buttonOption2.Add_Click({ Option2 })
    $form.Controls.Add($buttonOption2)

    $buttonExit = New-Object System.Windows.Forms.Button
    $buttonExit.Text = "Exit"
    $buttonExit.Location = New-Object System.Drawing.Point(50, 150)
    $buttonExit.Size = New-Object System.Drawing.Size(200, 30)
    $buttonExit.Add_Click({ $form.Close() })
    $form.Controls.Add($buttonExit)

    [void]$form.ShowDialog()
}

function Option1 {
    Write-Host "Option 1 selected"
    # Add your logic for Option 1 here
}

function Option2 {
    Write-Host "Option 2 selected"
    # Add your logic for Option 2 here
}

Show-FormMenu
Menu Options in PowerShell

In the above code, a form menu is created with two menu options (“Option 1” and “Option 2”) along with an “Exit” button. Each menu option is associated with a corresponding function (Option1 and Option2) that will be executed when the respective button is clicked.

You can customize the menu options, their functions, and the form itself to fit your specific needs. This provides a basic structure for creating a menu-driven PowerShell script using a form.

Making a Launcher Form

Here’s an example of how you can create a launcher form in PowerShell:

Add-Type -AssemblyName System.Windows.Forms

function Show-LauncherForm {
    $form = New-Object System.Windows.Forms.Form
    $form.Text = "PowerShell Launcher"
    $form.Size = New-Object System.Drawing.Size(300, 200)
    $form.FormBorderStyle = [System.Windows.Forms.FormBorderStyle]::FixedSingle

    $label = New-Object System.Windows.Forms.Label
    $label.Text = "Select an option to launch:"
    $label.Location = New-Object System.Drawing.Point(50, 20)
    $label.Size = New-Object System.Drawing.Size(200, 20)
    $form.Controls.Add($label)

    $buttonOption1 = New-Object System.Windows.Forms.Button
    $buttonOption1.Text = "Option 1"
    $buttonOption1.Location = New-Object System.Drawing.Point(50, 50)
    $buttonOption1.Size = New-Object System.Drawing.Size(200, 30)
    $buttonOption1.Add_Click({ Option1 })
    $form.Controls.Add($buttonOption1)

    $buttonOption2 = New-Object System.Windows.Forms.Button
    $buttonOption2.Text = "Option 2"
    $buttonOption2.Location = New-Object System.Drawing.Point(50, 100)
    $buttonOption2.Size = New-Object System.Drawing.Size(200, 30)
    $buttonOption2.Add_Click({ Option2 })
    $form.Controls.Add($buttonOption2)

    $buttonExit = New-Object System.Windows.Forms.Button
    $buttonExit.Text = "Exit"
    $buttonExit.Location = New-Object System.Drawing.Point(50, 150)
    $buttonExit.Size = New-Object System.Drawing.Size(200, 30)
    $buttonExit.Add_Click({ $form.Close() })
    $form.Controls.Add($buttonExit)

    [void]$form.ShowDialog()
}

function Option1 {
    Write-Host "Option 1 selected"
    # Add your logic for Option 1 here
}

function Option2 {
    Write-Host "Option 2 selected"
    # Add your logic for Option 2 here
}

Show-LauncherForm
Making a Launcher Form

In the above code, a launcher form is created with two options (“Option 1” and “Option 2”) and an “Exit” button. Each option is associated with a corresponding function (Option1 and Option2) that will be executed when the respective button is clicked.

Displaying the Launcher Form

Here’s an example of a launcher form created using PowerShell:

Add-Type -AssemblyName System.Windows.Forms

# Define the launcher form
$form = New-Object System.Windows.Forms.Form
$form.Text = "PowerShell Launcher"
$form.Size = New-Object System.Drawing.Size(300, 200)
$form.FormBorderStyle = [System.Windows.Forms.FormBorderStyle]::FixedSingle

# Add a label
$label = New-Object System.Windows.Forms.Label
$label.Text = "Select an option to launch:"
$label.Location = New-Object System.Drawing.Point(50, 20)
$label.Size = New-Object System.Drawing.Size(200, 20)
$form.Controls.Add($label)

# Add buttons for options
$buttonOption1 = New-Object System.Windows.Forms.Button
$buttonOption1.Text = "Option 1"
$buttonOption1.Location = New-Object System.Drawing.Point(50, 50)
$buttonOption1.Size = New-Object System.Drawing.Size(200, 30)
$buttonOption1.Add_Click({ Option1 })
$form.Controls.Add($buttonOption1)

$buttonOption2 = New-Object System.Windows.Forms.Button
$buttonOption2.Text = "Option 2"
$buttonOption2.Location = New-Object System.Drawing.Point(50, 100)
$buttonOption2.Size = New-Object System.Drawing.Size(200, 30)
$buttonOption2.Add_Click({ Option2 })
$form.Controls.Add($buttonOption2)

# Add an exit button
$buttonExit = New-Object System.Windows.Forms.Button
$buttonExit.Text = "Exit"
$buttonExit.Location = New-Object System.Drawing.Point(50, 150)
$buttonExit.Size = New-Object System.Drawing.Size(200, 30)
$buttonExit.Add_Click({ $form.Close() })
$form.Controls.Add($buttonExit)

# Show the form
[void]$form.ShowDialog()

# Option 1 function
function Option1 {
    Write-Host "Option 1 selected"
    # Add your logic for Option 1 here
}

# Option 2 function
function Option2 {
    Write-Host "Option 2 selected"
    # Add your logic for Option 2 here
}
Displaying the Launcher Form

When you run the above code, it will display a launcher form with two options (“Option 1” and “Option 2”) and an “Exit” button. You can customize the options and their associated functions according to your requirements. The form will remain open until you select an option or click the “Exit” button.

Elevate your PowerShell scripting to new heights with GUI menus. Empower yourself to create dynamic and user-friendly interfaces, automate complex tasks, and enhance your productivity. By harnessing the power of PowerShell’s GUI capabilities, you can streamline your workflow, impress your users, and unlock the full potential of your scripts.